0=y^2-54

Solution for 0=y^2-54 equation:

0=y^2-54

We move all terms to the left:

0-(y^2-54)=0

We add all the numbers together, and all the variables

-(y^2-54)=0

We get rid of parentheses

-y^2+54=0

We add all the numbers together, and all the variables

-1y^2+54=0

a = -1; b = 0; c = +54;
Δ = b2-4ac
Δ = 02-4·(-1)·54
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{6}}{2*-1}=\frac{0-6\sqrt{6}}{-2}
=-\frac{6\sqrt{6}}{-2}
=-\frac{3\sqrt{6}}{-1}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{6}}{2*-1}=\frac{0+6\sqrt{6}}{-2}
=\frac{6\sqrt{6}}{-2}
=\frac{3\sqrt{6}}{-1}
$